How many host addresses are available on the 192.168.10.128/26 network?Ī /26 prefix gives 6 host bits, which provides a total of 64 addresses, because 2 6 = 64. The formula 2 n, where n is the number of bits borrowed, is used to calculate the available number of subnets when borrowing a specific number of bits. How many bits must be borrowed from the host portion of an address to accommodate a router with five connected networks?Įach network that is directly connected to an interface on a router requires its own subnet.The number of bits that are borrowed would be two, thus giving a total of 4 useable subnets:īecause 2 bits are borrowed, the new subnet mask would be /26 or 255.255.255.192 Subnet mask 255.255.255.224 Answers Explanation & Hints: What is the network address and subnet mask of the second useable subnet? An administrator wants to create four subnetworks from the network address 192.168.1.0/24.Last Updated on Februby Admin CCNA1 v7 – ITNv7 – Modules 11 – 13: IP Addressing Exam Answers 2020 Correct 100% Cisco Netacad ITN Version 7.00 CCNA 1 v7 Modules 11 – 13: IP Addressing Exam Answers 2020 2021 – Introduction to Networks ITN (Version 7.00) – IP Addressing Exam Answers 2020 2021
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